- 《鐵路救援：軌道謎題》將於 6 月 30 日在行動裝置上推出
- 包含 500 個充滿挑戰的關卡，玩家需繪製鐵道軌跡來拯救可愛的卡通市民
- 在重建故鄉的同時，發掘獨特角色的背景故事與隱藏敘事
火車主題的解謎遊戲在行動遊戲領域持續受到關注。除了 Short Circuit Studios 的《迷你小火車》等作品外，Infinity Games 將於 6 月 30 日推出《鐵路救援》——但這款解謎體驗有何特別之處？
《鐵路救援》定位為腦力訓練遊戲，提供簡易卻引人入勝的玩法：滑動繪製鐵路軌道，避開障礙物，並引導所有圓滾滾的市民安全抵達終點。遊戲擁有 500 個精心設計的關卡，充滿逐步提升難度的謎題挑戰。
除了核心玩法，玩家可透過階段性進展，逐步重建破敗的故鄉。鮮明的美術風格呈現出一系列獨特角色——在保持視覺一致性的同時，每位居民都擁有鮮明的個性特質。
全員上車！
遊戲還包含實用的強化道具與提示系統，協助玩家應對棘手關卡。開發團隊承諾將推出競爭性的排行榜與季節性內容更新，所有功能均可透過可選的應用程式內購支援，且遊戲上市即提供完整的離線遊玩體驗。
《鐵路救援》的成功或許取決於其巧妙的謎題設計，儘管卡通美學風格可能同時兼具吸引力與兩極評價。遊戲上市即提供數百個關卡，追求放鬆卻不失動腦樂趣的玩家應english
https://brainly.com/question/30748668
SPJ
A researcher wants to test the claim that convicted burglars spend an average of 18.7 months in jail. She takes a random sample of 11 such cases from court files and finds that in Construct a 95% confidence interval. What does the interval assert?
The confidence interval asserts that the researcher can be 95% confident that the true population mean falls within the calculated interval. In other words, if the researcher were to repeat the sampling process many times and construct a confidence interval each time, approximately 95% of those intervals would contain the true population mean.
To construct a 95% confidence interval for the average jail time spent by convicted burglars, we can use the following formula:
Confidence Interval = sample mean ± (critical value * standard deviation / sqrt(sample size))
First, we need to find the critical value corresponding to a 95% confidence level. Since the sample size is small (n = 11), we should use a t-distribution. The degrees of freedom for a sample size of 11 is (n - 1) = 10. Using a t-table or statistical software, the critical value for a 95% confidence level with 10 degrees of freedom is approximately 2.228.
Next, we calculate the sample mean and sample standard deviation from the given data:
Sample mean (x') = (23 + 15 + 18 + 17 + 19 + 24 + 22 + 21 + 23 + 27 + 16) / 11 = 20.545
Sample standard deviation (s) = sqrt(((23 - 20.545)^2 + (15 - 20.545)^2 + ... + (16 - 20.545)^2) / (11 - 1)) ≈ 3.481
Now we can construct the confidence interval:
Confidence Interval = 20.545 ± (2.228 * 3.481 / sqrt(11))
Calculating the expression inside the parentheses:
2.228 * 3.481 / sqrt(11) ≈ 2.689
Confidence Interval = 20.545 ± 2.689
Lower bound = 20.545 - 2.689 ≈ 17.856
Upper bound = 20.545 + 2.689 ≈ 23.234
Therefore, the 95% confidence interval for the average jail time spent by convicted burglars is approximately 17.856 to 23.234 months.
The confidence interval asserts that the researcher can be 95% confident that the true population mean falls within the calculated interval. In other words, if the researcher were to repeat the sampling process many times and construct a confidence interval each time, approximately 95% of those intervals would contain the true population mean.
Regarding the claim that convicted burglars spend an average of 18.7 months in jail, we can see that 18.7 falls within the confidence interval (17.856 to 23.234). This means that the claim is consistent with the data, as the confidence interval includes the value of 18.7. However, we cannot definitively conclude that the claim is true or false based solely on the confidence interval. The confidence interval provides a range of plausible values for the population mean, but it does not provide certainty about any specific claim.
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